Q105 / 200 · TS EAMCET 2001 · Mathematics

Using the Trapezoidal rule, the approximate value of $\int_1^4 y d x$ Figure

  • A
    $0.1833$
  • B
    $1.1833$
  • Correct answer
    C
    $2.1833$
  • D
    $3.1833$

Solution

We have, $\begin{aligned} h & =\frac{4-1}{3}=1 \\ \int_1^2 y d x & =\frac{1}{2} h\left[y_1+2\left(y_2+y_3\right)+y_4\right] \\ & =\frac{1}{2} \cdot 1[0.7111+2(0.7222+0.7333)+0.7444] \\ & =2.1833\end{aligned}$ [OBJECT END

Hence, the correct answer is option: 'C'.

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