Q104 / 200 · TS EAMCET 2001 · Mathematics
$\int_{-1}^1\left(a x^3+b x\right) d x=0$ for
- Correct answerAany value of $a$ and $b$
- B$a>0, b>0$ only
- C$a>0, b>0$ only
- D$a < 0, b>0$ only
Solution
$\begin{array}{r}\int_{-1}^1\left(a x^3+b x\right) d x=\left[a \frac{x^4}{4}+b \frac{x^2}{2}\right]_{-1}^1 \\ =\frac{a}{4}(1-1)+\frac{b}{2}(1-1)=0\end{array}$
For any value of $a$ and $b$.
Hence, the correct answer is option: 'A'.