Q111 / 160 · AP EAMCET 2025 (23 MAY SHIFT 1) · Mathematics
$\int \frac{\sec ^2 x}{(\sec x+\tan x)^{5 / 2}} d x=$
- A$-\frac{(\sec x+\tan x)^{5 / 2}}{5}-\frac{(\sec x+\tan x)^{7 / 2}}{7}+c$
- B$-\frac{(\sec x-\tan x)^{5 / 2}}{5}-\frac{(\sec x-\tan x)^{7 / 2}}{7}+c$
- C$-\frac{(\sec x+\tan x)^{3 / 2}}{3}-\frac{(\sec x+\tan x)^{7 / 2}}{7}+c$
- Correct answerD$-\frac{(\sec x-\tan x)^{3 / 2}}{3}-\frac{(\sec x-\tan x)^{7 / 2}}{7}+c$
Hence, the correct answer is option: 'D'.