If $\int \frac{\mathrm{dx}}{1-\sin ^4 \mathrm{x}}=\mathrm{A} \tan \mathrm{x}+\mathrm{B} \operatorname{Tan}^{-1}(\sqrt{2} \tan \mathrm{x})+\mathrm{C}$, then $\mathrm{A}^2-\mathrm{B}^2=$

• A

  $\frac{1}{2}$
• B

  $\frac{3}{4}$
• C

  $\frac{1}{4}$
• Correct answer
  D

  $\frac{1}{8}$

Hence, the correct answer is option: 'D'.