$\int \frac{x^4-16 x^2+2 x+8}{x^3-4 x^2+2} d x=$

• Correct answer
  A

  $\frac{x^2+8 x+c}{2}$
• B

  $x^2+8 x+c$
• C

  $x^3-4 x+c$
• D

  $\frac{x^2-8 x+c}{2}$

Hence, the correct answer is option: 'A'.