$\int \frac{1}{9 \cos ^2 x-24 \sin x \cos x+16 \sin ^2 x} d x=$

• Correct answer
  A

  $\frac{\cos x}{4(3 \cos x-4 \sin x)}+c$
• B

  $\frac{\sin x}{4(3 \cos x-4 \sin x)}+c$
• C

  $\frac{\cos x}{3 \cos x-4 \sin x}+c$
• D

  $\frac{\sin x}{3 \cos x-4 \sin x}+c$

Hence, the correct answer is option: 'A'.