If $\int \frac{1}{\cot \frac{x}{2} \cot \frac{x}{3} \cot \frac{x}{6}} d x=A \log \left|\cos \frac{x}{2}\right|+B \log \left|\cos \frac{x}{3}\right|+C \log \left|\cos \frac{x}{6}\right|+k$ then $\mathrm{A}+\mathrm{B}+\mathrm{C}=$

• Correct answer
  A

  7
• B

  11
• C

  -7
• D

  1

Hence, the correct answer is option: 'A'.