JEE Main 2022 (26 Jun Shift 2) Q13

Q13 / 90 · JEE Main 2022 (26 Jun Shift 2) · Chemistry

Correct answer
A
B
C
D

Solution

It is oxymercuration–demercuration reaction. In this an alkene is treated with mercury(II) acetate, and the product is treated with sodium borohydride. The net result is a Markovnikov addition product without rearrangement.

Hence, the correct answer is option: 'A'.

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