Q74 / 90 · JEE Main 2021 (17 Mar Shift 2) · Physics

Two particles $A$ and $B$ of equal masses are suspended from two massless springs of spring constants $K_{1}$ and $K_{2}$ respectively.If the maximum velocities during oscillations are equal, the ratio of the amplitude of $A$ and $B$ is

Solution

$A_{1} ω_{1} = A_{2} ω_{2}$

$A_{1} \sqrt{\frac{k_{1}}{m}} = A_{2} \sqrt{\frac{k_{2}}{m}}$

$\frac{A_{1}}{A_{2}} = \sqrt{\frac{k_{2}}{k_{1}}}$

Hence, the correct answer is option: 'D'.