Q73 / 90 · JEE Main 2021 (17 Mar Shift 2) · Physics

The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of 15Ω resistance is connected across BD. Calculate the current through the galvanometer when a potential difference of 10 V is maintained across AC.

Figure

  • A
    2.44μA
  • B
    2.44 mA
  • Correct answer
    C
    4.87 mA
  • D
    4.87μA

Solution

Figure

x-10100+x-y15+x-010=0

53x-20y=30  ……(1)

y-1060+y-x15+y-05=0

17y-4x=10  ……(2)

on solving (1) & (2)

x=0.865

y=0.792

ΔV=0.073R=15 Ω

⇒i=4.87 mA

Hence, the correct answer is option: 'C'.

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