Q189 / 200 · Manipal (MET) 2010 · Physics

Two parallel plates of area $A$ are separated by two different dielectrics as shown in figure. The net capacitance is Figure

  • A
    $\frac{\varepsilon_0 A}{2 d}$
  • B
    $\frac{\varepsilon_0 A}{d}$
  • C
    $\frac{3 \varepsilon_0 A}{d}$
  • Correct answer
    D
    $\frac{4 \varepsilon_0 A}{3 d}$

Solution

The net capacitance $C=\frac{\varepsilon_0 A}{\frac{d_1}{K_1}+\frac{d_2}{K_2}}$ $=\frac{\varepsilon_0 A}{\frac{d}{2}\left(\frac{1}{1}+\frac{1}{2}\right)}=\frac{4 \varepsilon_0 A}{3 d}$

Hence, the correct answer is option: 'D'.

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