Q127 / 180 · NEET 2014 · Physics

Two identical long conducting wires AOB and COD are placed at right angle to each other, with one above other such that ‘ O ’ is their common point for the two. The wires carry I1 and I2 currents, respectively. Point ‘ I ’ is lying at distance ‘ d ’ from ‘ O ’ along a direction perpendicular to the plane containing the wires. The magnetic field at the point ‘ P ’ will be:

  • A
    μ02πdI1I2
  • B
    μ02πdI1+I2
  • C
    μ02πdI12-I22
  • Correct answer
    D
    μ02πdI12+I221/2

Solution

Figure
B→ due to wire 1 B→1=μ0i12πdi^
B→ due to wire 2 B→2=μ0i22πd-j^
Bnet=μ02πd i12+i22

Hence, the correct answer is option: 'D'.

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