Q48 / 54 · KVPY 2017 (5 Nov SA) · Physics
Two different liquids of same mass are kept in two identical vessels, which are placed in a freezer that extracts heat from them at the same rate causing each liquid to transform into a solid. The schematic figure below shows the temperature T vs time t plot for the two materials. We denote the specific heat in the liquid statusto be $C_{L 1}$ and $C_{L 2}$ for materials 1 and 2 respectively, and latent heats of fusion $U_{1}$ and $U_{2}$ respectively.

Choose the correct option.

Choose the correct option.
- A$C_{\text {L1 }}>C_{L 2}$ and $U_{1} < U_{2}$
- B$C_{\mathrm{L} 1}>\mathrm{C}_{\mathrm{L} 2}$ and $\mathrm{U}_{1}>\mathrm{U}_{2}$
- Correct answerC$\mathrm{C}_{\mathrm{L1}} < \mathrm{C}_{\mathrm{L} 2}$ and $\mathrm{U}_{1}>\mathrm{U}_{2}$
- D$C_{\mathrm{L1}} < \mathrm{C}_{\llcorner 2}$ and $U_{1} < U_{2}$
Solution
Let Refrigerater extract $Q$ joul/per second
$\text { Q.t } \Rightarrow \mathrm{ms}\left(\mathrm{T}_{\mathrm{f}}-\mathrm{T}\right)$
Higher the specific heat, Higher the slope
Hence, the correct answer is option: 'C'.