Q76 / 120 · NEET 2011 (Mains) · Physics
Three charges, each $+q$, are placed at the corners of an isosceles triangle $A B C$ of sides $B C$ and $A C, 2 a . D$ and $E$ are the mid points of $B C$ and $C A$. The work done in taking a charge $Q$ from $D$ to $E$ is


- A$\frac{e q Q}{8 \pi \varepsilon_0 a}$
- B$\frac{q Q}{4 \pi \varepsilon_0 a}$
- Correct answerCzero
- D$\frac{3 q Q}{4 \pi \varepsilon_0 a}$
Solution
$$
\text { Here, } A C=B C
$$

$$ \begin{aligned} & V_D=V_E=V \\ & W=Q\left[V_E-V_D\right] \\ & W=Q[V-V] \\ & W=0 \end{aligned} $$

$$ \begin{aligned} & V_D=V_E=V \\ & W=Q\left[V_E-V_D\right] \\ & W=Q[V-V] \\ & W=0 \end{aligned} $$
Hence, the correct answer is option: 'C'.