Three capacitors each of capacitance $C$ and of breakdown voltage $\mathrm{V}$ are joined in series. The capacitance and breakdown voltage of the combination will be :

• A

  $3 \mathrm{C}, 3 \mathrm{~V}$
• B

  $\frac{\mathrm{C}}{3}, \frac{\mathrm{V}}{3}$
• C

  $3 \mathrm{C}, \frac{\mathrm{V}}{3}$
• Correct answer
  D

  $\frac{\mathrm{C}}{3}, 3 \mathrm{~V}$

Hence, the correct answer is option: 'D'.