In the following circuit, the equivalent capacitance between terminal $A$ and terminal $B$ is :

• A

  $1 \mu \mathrm{F}$
• B

  $0.5 \mu \mathrm{F}$
• C

  $4 \mu \mathrm{F}$
• Correct answer
  D

  $2 \mu \mathrm{F}$

Solution

Given circuit is balanced Wheatstone bridge
$\begin{aligned} C_{A B} & =1+1 \\ & =2 \mu F\end{aligned}$

Hence, the correct answer is option: 'D'.