Q7 / 104 · NTA Abhyas (JEE Main) 2020 · Mathematics · Indefinite Integration

The value of the integral ∫sin⁡xx6xcosx-sin⁡xx2dx is

(where, c is an arbitrary constant)

  • A
    sinxx+c
  • B
    sinxx2+c
  • C
    sin7xx7+c
  • Correct answer
    D
    sin7x7x7+c

Solution

Put sinxx=t.
Then, I=∫t6dt=t77+c

Hence, the correct answer is option: 'D'.

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