Q4 / 104 · NTA Abhyas (JEE Main) 2020 · Mathematics · Indefinite Integration

If the integral I=∫xx-3x+3x-1x-2x+1dx=fx+C (where, x>0 and C is the constant of integration) and f1=-13, then the value of f9 is equal to

  • A
    3
  • B
    6
  • Correct answer
    C
    9
  • D
    12

Solution

Given integral is I=∫x-13x-12dx
=∫x-1dx
=23x32-x+C
∴fx=23x32-x
⇒f9=18-9=9

Hence, the correct answer is option: 'C'.

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