The value oflimx→1^(+)(∫1xt-1dt)/(sin⁡(x-1)) is equal to

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MARKS Content Team · Accepted Answer

Correct answer: 0. Given: lim x→1^(+) (∫ 1 x (t−1) dt)/(sin(x−1)) Using L’Hospital’s rule and leibuitzrule, l= lim x→1^(+) (d dx ∫ 1 x (t−1) dt)/(d dx) sin x−1 lim x→1^(+) (x−1)/(cos x−1) =0/1 =0

The value of $\lim_{x \to 1^{+}} \frac{\int_{1}^{x} |t - 1| dt}{\sin (x - 1)}$ is equal to

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More Limits Questions

The value oflimx→1+∫1xt-1dtsin⁡(x-1) is equal to

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More Limits Questions

The value of $\lim_{x \to 1^{+}} \frac{\int_{1}^{x} |t - 1| dt}{\sin (x - 1)}$ is equal to