The value of limx→0(log(1+x+x^2)+log(1−x+x^2))/(secx−cosx) is equal to

Question

MARKS Content Team · Accepted Answer

Correct answer: (B) 1. lim x → 0 (log 1 + x + x^2 + log 1 - x + x^2)/(sec x - cos x) = lim x → 0 (log 1 + x 2^2 - x^2)/(1 - cos^(2 ) x / cos x) = lim x → 0 (log 1 + x^2 + x^4)/(sin x tan x) = lim x → 0 (log 1 + x^2 1 + x^2)/(x^2 1 + x^2) · x^2 1 + x^2 · 1/(sin x x) · (tan x)/x · x^2 = 1 as lim x → 0 (log 1 + x)/x = 1

The value of $\lim_{x \to 0} \frac{\log (1 + x + x^{2}) + \log (1 - x + x^{2})}{\sec x - \cos x}$ is equal to

Solution

More Limits Questions

The value of limx→0log(1+x+x2)+log(1−x+x2)secx−cosx is equal to

Solution

More Limits Questions

The value of $\lim_{x \to 0} \frac{\log (1 + x + x^{2}) + \log (1 - x + x^{2})}{\sec x - \cos x}$ is equal to