The value of limx→0⁡(9ln⁡2-cos⁡25x)/(5ln^2sin⁡3x+1⁡) is equal to

Question

MARKS Content Team · Accepted Answer

Correct answer: 62.5. limx→0⁡(9ln2-cos⁡25x)/(5ln^2sin⁡3x+1)=limx→0⁡(9ln1+1-cos⁡25x)/(5ln^21+sin⁡3x) =limx→0⁡(91-cos⁡25x)/(5sin⁡3x^2) ⇒limx→0⁡(925x^2)/(103x^2)=625/10=62.5

The value of $\lim_{x \to 0} \frac{9 \ln (2 - \cos 25 x)}{5 \ln^{2} (\sin 3 x + 1)}$ is equal to

Solution

More Limits Questions

The value of limx→0⁡9ln⁡2-cos⁡25x5ln2sin⁡3x+1⁡ is equal to

Solution

More Limits Questions

The value of $\lim_{x \to 0} \frac{9 \ln (2 - \cos 25 x)}{5 \ln^{2} (\sin 3 x + 1)}$ is equal to