The stopping potential for electrons emitted from a photosensitive surface illuminated by light of wavelength $491 \mathrm{nm}$ is $0.710 \mathrm{V}.$ When the incident wavelength is changed to a new value, the stopping potential is $1.43 \mathrm{V}.$ The new wavelength is :

• Correct answer
  A

  $382 \mathrm{nm}$
• B

  $309 \mathrm{nm}$
• C

  $329 \mathrm{nm}$
• D

  $400 \mathrm{nm}$

Hence, the correct answer is option: 'A'.