Q39 / 201 · NTA Abhyas (NEET) 2020 · Physics · Atomic Physics

The radius of hydrogen atom in its ground state is 5.3×10-11 m. After collision with an electron it is found to have a radius of 21.2 × 10-11 m. What is the principal quantum number n of the final state of the atom?

  • A
    n=4
  • Correct answer
    B
    n=2
  • C
    n=16
  • D
    n=3

Solution

                         r∝n2

                       rfri=nfni2

         21.2 ×10-115.3×10-11 = n12

                      n2=4

                        n=2

Hence, the correct answer is option: 'B'.

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