The binding energy per nucleon of deuteron $\left({}_1^2\text{H}\right)$ and helium nucleus $\left({}_2^4\text{He}\right)$ is $\text{1.1 }\text{Me}\text{V}$ and $\text{7 }\text{Me}\text{V}$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

• A

  $\text{13.9 }\text{Me}\text{V}$
• B

  $\text{26.9 }\text{Me}\text{V}$
• Correct answer
  C

  $\text{23.6 }\text{Me}\text{V}$
• D

  $\text{19.2 }\text{Me}\text{V}$

Hence, the correct answer is option: 'C'.