Q40 / 201 · NTA Abhyas (NEET) 2020 · Physics · Atomic Physics

If the radius of first Bohr's orbit of hydrogen is x, then the de-Broglie wavelength of the electron in its 3rd orbit is

  • A
    2πx
  • Correct answer
    B
    6πx
  • C
    9x
  • D
    x3

Solution

r n ∝ n 2 z
for Hydrogen atom, (z=1), r n ∝ n 2
r 1 =x
r 3 =9x
Now, ⇒ 2πr 3 =nλ
⇒λ= 2 πr 3 3
⇒λ= 2 3 π×9x
∴ λ=6πx

Hence, the correct answer is option: 'B'.

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