Q47 / 160 · TS EAMCET 2017 · Mathematics
The probability distribution of a random variable $X$ is given below
The variance of $X$ is
The variance of $X$ is
- A1.6
- B0.24
- Correct answerC0.84
- D0.75
Solution
$$
\text { We have, }
$$
$$ \text { Variance } \begin{aligned} \left(\sigma^2\right) & =\Sigma P_i X_i^2-\left(\Sigma P_i X_i\right)^2 \\ & =3.4-(1.6)^2=3.4-2.56=0.84 \end{aligned} $$
$$ \text { Variance } \begin{aligned} \left(\sigma^2\right) & =\Sigma P_i X_i^2-\left(\Sigma P_i X_i\right)^2 \\ & =3.4-(1.6)^2=3.4-2.56=0.84 \end{aligned} $$
Hence, the correct answer is option: 'C'.