The number of real circles cutting orthogonally the circle $x^{2}+y^{2}+2 x-2 y+7=0$ is

Given, equation of circle is $x^{2}+y^{2}+2 x-2 y+7=0$ Here, radius of the circle $\begin{aligned} &=\sqrt{(1)+(-1)^{2}-7} \\ &=\sqrt{1+1-7}=\sqrt{-5} \\ &=\text { imaginary } \end{aligned}$ $\therefore$ Given circle is an imaginary circle. Hence, number of real circles cutting orthogonally the given imaginary circle is zero.