Q20 / 125 · BITSAT 2011 · Chemistry

The number of coulombs required for the deposition of $108 \mathrm{~g}$ of silver is

  • Correct answer
    A
    96500
  • B
    48250
  • C
    193000
  • D
    10000

Solution

Amt. deposited $=\frac{\text { E. wt } \times \text { Q }}{96500}$; $$ 107.870=\frac{107.870}{96500} \times \mathrm{Q} ; \quad \therefore \mathrm{Q}=96500 \mathrm{C} $$

Hence, the correct answer is option: 'A'.

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