Q30 / 46 · NTA Abhyas (JEE Main) 2020 · Physics · Motion In One Dimension

The motion of a body falling from rest in a resistive medium is described by the equation dvdt=a-bv, where a and b are constants. The velocity at any time t is

  • A
    a(1-b2t)
  • Correct answer
    B
    ab(1-e-bt)
  • C
    abe-t
  • D
    ab2(1-t)

Solution

dvdt=a-bv

or ∫0vdva-bv=∫0tdt

or -1bloga-bv0v=t

or a-bva=e-bt

or a-bav=e-bt

v=ab(1-e-bt)

Hence, the correct answer is option: 'B'.

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