Q29 / 46 · NTA Abhyas (JEE Main) 2020 · Physics · Motion In One Dimension

The following figure gives the movement of an object. Select the correct statement from the given choices.

Figure

  • Correct answer
    A
    The total distance travelled by the object is 975 m
  • B
    The maximum acceleration of the object is 2 m s-2
  • C
    The maximum deceleration happened between 25th and 35th seconds
  • D
    The object was at rest between 10th and 15th seconds

Solution

Figure

The total distance travelled by the object will be area of given graph in the figure.

Total distance s=75+225+125+100+400+50

=975 m

Hence, the correct answer is option: 'A'.

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