A particle goes from A to B with a speed of 40 km/h and B to C with a speed of 60 km/h . If AB=6 BC , the average speed in km/h between A and C is

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MARKS Content Team · Accepted Answer

Correct answer: 42. V_av = (distance travelled)/(time taken) ⇒ V_av = (AB + BC)/(AB 4 0) + BC/(6 0) ⇒ V_av = (6BC + BC)/(6BC 4 0) + BC/(6 0) V_av = (7 × 2 4 0)/(3 6 + 4) ⇒ V_av = (7 × 2 4 0)/(4 0) ⇒ V_av = 4 2 km/h

A particle goes from $A$ to $B$ with a speed of $40 km/h$ and $B$ to $C$ with a speed of $60 km/h$ . If $AB = 6 BC$ , the average speed in $km/h$ between $A$ and $C$ is

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