A point moves in the $x-y$ plane according to $x=A\sin \omega t$ and $y=A\left(1–\text{cos}\omega t\right)$ where $A$ and $\omega$ are positive constants. The distance traversed by the point during the time $\tau$ is

• A

  $\frac{A{\omega }^2}{\tau }$
• B

  $A{\omega }^2\tau$
• Correct answer
  C

  $A\omega \tau$
• D

  $\frac{A\omega }{\tau }$

Hence, the correct answer is option: 'C'.