Q23 / 160 · TS EAMCET 2019 (03 May Shift 1) · Chemistry

The molality (in mol $\mathrm{kg}^{-1}$ ) of 1 mole of solute in $50 \mathrm{~g}$ of solvent is

  • A
    10
  • Correct answer
    B
    20
  • C
    30
  • D
    40

Solution

Given, Moles of solute $(n)=1 \mathrm{~mol}$ Mass of solvent $\left(w_A\right)=50 \mathrm{~g}$ $\because$ Molality $(m)=\frac{n \times 1000}{w_A(\text { in g) }}$ $\therefore \quad m=\frac{1000}{50}=20 \mathrm{~mol} \mathrm{~kg}^{-1}$ Hence, option (2) is the correct answer.

Hence, the correct answer is option: 'B'.

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