Q9 / 160 · TS EAMCET 2019 (04 May Shift 2) · Chemistry

The approximate molarity of a solution in $\mathrm{mol} \mathrm{L}^{-1}$ that contains $13.50 \mathrm{~g}$ of $\mathrm{NaCl}$ dissolved in $452 \mathrm{~mL}$ of water is

  • A
    0.25
  • Correct answer
    B
    0.51
  • C
    1.0
  • D
    1.2

Solution

Given, Mass of $\mathrm{NaCl}=13.5 \mathrm{~g}$ Volume of solution $=452 \mathrm{~mL}$ Molarity of solution $(M)$ $=\frac{\text { Mass of } \mathrm{NaCl}}{\text { Molar mass of } \mathrm{NaCl}} \times \frac{1}{\text { Volume of solution in (L) }}$ $$ M=\frac{13.50}{58.5} \times \frac{1000}{452} \mathrm{~mol} / \mathrm{L} \Rightarrow M=0.51 \mathrm{~mol} / \mathrm{L} $$

Hence, the correct answer is option: 'B'.

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