Q9 / 160 · TS EAMCET 2022 (18 Jul Shift 1) · Chemistry

The amount of $50 % (w / w)$ solution of hydrochloric acid required to react with $200 g$ of ${CaCO}_{3}$ would be

A
$73 g$
Correct answer
B
$292 g$
C
$146 g$
D
$100 g$

Solution

Reaction would be
${CaCO}_{3} + 2 HCl \to {CaCl}_{2} + {CO}_{2} + H_{2} O$
Equivalent of $HCl =$ Equivalent of ${CaCO}_{3}$
Thus, $\frac{w}{36.5} = \frac{200}{50}$
$∴ w = 146 gHCl$
Given $w / w of solution = 50 %$
$\frac{w}{w} = \frac{weight of solute}{weight of solution} \times 100 50 = \frac{146}{Weight of solution} \times 100 Weight of solution = 292 g$

Hence, the correct answer is option: 'B'.

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The amount of 50%w/w solution of hydrochloric acid required to react with 200 g of CaCO3 would be

Solution

Relevant Questions

The amount of $50 % (w / w)$ solution of hydrochloric acid required to react with $200 g$ of ${CaCO}_{3}$ would be