The minimum value of the function fx=(tan⁡x)/(3+2tan⁡x), ∀x∈0,(π)/2 is

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Correct answer: (A) 0. If x∈0,(π)/2, tanx∈0,∞ Let, tanx=t i.e. y=t/(3+2t), t∈0,∞ ⇒3y+2ty=t ⇒t=3y/(1-2y)≥0 ⇒y∈0,1/2 Hence, the minimum value of the function=0

The minimum value of the function $f (x) = \frac{\tan x}{3 + 2 \tan x}, \forall x \in [0, \frac{π}{2})$ is

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The minimum value of the function fx=tan⁡x3+2tan⁡x, ∀x∈0,π2 is

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More Functions Questions

The minimum value of the function $f (x) = \frac{\tan x}{3 + 2 \tan x}, \forall x \in [0, \frac{π}{2})$ is