Q3 / 87 · NTA Abhyas (JEE Main) 2020 · Mathematics · Functions

sinax+cosax and |sinx|+|cosx| are periodic with the same fundamental period, if a equals to

  • A
    0
  • B
    1
  • C
    2
  • Correct answer
    D
    4

Solution

sinax+cosax=2sinax+π4

So, fundamental period =2πa

Let, T be the fundamental period of sinx+cosx

So sin(x+T)+cos(x+T)= sinx+cosx.

Squaring both sides, we get,

1+sin(2x+2T)=1+sin2x

Therefore, the fundamental period of sinx+cosx is π2

Hence, 2πa=π2

⇒a=4

Hence, the correct answer is option: 'D'.

More Functions Questions