Q4 / 87 · NTA Abhyas (JEE Main) 2020 · Mathematics · Functions

For p>2 and x∈R, if the number of natural numbers in the range of fx=x2+2x+px2+2x+2 is 3, then the value of p is equal to

  • A
    3
  • B
    4
  • Correct answer
    C
    5
  • D
    6

Solution

Here, fx=1+p-2x+12+1∈1,p-1
If there are 3 natural numbers in the range ⇒p-1=4⇒p=5

Hence, the correct answer is option: 'C'.

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