Q126 / 200 · NEET 2023 (All India) · Physics

The magnitude and direction of the current in the following circuit is

A
$1.5 A$ from $B$ to $A$ through $E$
B
$0.2 A$ from $B$ to $A$ through $E$
Correct answer
C
$0.5 A$ from $A$ to $B$ through $E$
D
$\frac{5}{9} A$ from $A$ to $B$ through $E$

Solution

Let the direction of electric current in the circuit be $i$ from $A to B$ . Using Kirchhoff's law in clockwise direction, we get
$- (i \times 2) + 10 - 5 - (i \times 1) - (i \times 7) = 0 \Rightarrow 5 = 10 i \Rightarrow i = \frac{5}{10} = 0.5 A$

Hence, the correct answer is option: 'C'.

Relevant Questions

A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of2025Kirchoffs Laws
For the circuit shown in the figure, the current I will be2020 (Phase 2)Kirchoffs Laws
For the circuit given below, the Kirchhoff s loop rule for the loop B C D E B is given by the equation2020 (Phase 2)Kirchoffs Laws
The potential difference V A - V B between the points A and B in the given figure is2016 (Phase 2)Kirchoffs Laws
In the circuit shown the cells and have negligible resistances. For , and the galvanometer (G) shows no deflection. The value of is2012 (Screening)Kirchoffs Laws
In the circuit shown in the figure, if potential at point is taken to be zero, the potential at point is2011 (Mains)Kirchoffs Laws