Q126 / 200 · NEET 2012 (Screening) · Physics
In the circuit shown the cells $A$ and $B$ have negligible resistances. For $V_A=12 \mathrm{~V}$, $R_1=500 \Omega$ and $R=100 \Omega$ the galvanometer (G) shows no deflection. The value of $V_B$ is


- A$4 \mathrm{~V}$
- Correct answerB$2 \mathrm{~V}$
- C$12 \mathrm{~V}$
- D$6 \mathrm{~V}$
Solution
Applying Kirchhoff's law
$500 I+100 I=12$
So, $I=\frac{12 \times 10^{-2}}{6}=2 \times 10^{-2}$
Hence, $V_B=100\left(2 \times 10^{-2}\right)=2 \mathrm{~V}$
Hence, the correct answer is option: 'B'.