Q50 / 87 · NTA Abhyas (JEE Main) 2020 · Mathematics · Functions

The function f:0,7→0,70 where fx=x3-12x2+45x, is

  • A
    one-one & onto
  • Correct answer
    B
    many-one & onto
  • C
    one-onto & into
  • D
    many-one & into

Solution

f'x=3x2-24x+45
=3x2-8x+15=3x-3x-5
∴f'x changes its sign for x∈0,7
∴fx is many-one
Now f0=0, f5=50, 
f3=54, f7=70
∴Range∈0,70=co-domain
∴fx→onto

Hence, the correct answer is option: 'B'.

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