Q165 / 180 · KCET 2019 · Physics

The equation of a stationary wave is \( y=2 \sin \left(\frac{\Pi x}{15}\right) \cos (48 \pi t) \). The distance between a node
and its next antinode is

  • A
    \( 22.5 \) units
  • Correct answer
    B
    \( 7.5 \) units
  • C
    \( 30 \) units
  • D
    \( 1.5 \) units

Solution

(B) \( y=2 \sin \left(\frac{\Pi x}{15}\right) \cos (48 \pi t) \) \( \frac{2 \pi}{\lambda}=\frac{I I}{15} \) \( \lambda=30 \) \( \frac{\lambda}{4}=\frac{30}{4}=7.5 \)

Hence, the correct answer is option: 'B'.

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