Q166 / 180 · KCET 2019 · Physics
In the given circuit, the current through \( 2 \Omega \) resistor is
- Correct answerA\( 0.4 \mathrm{~A} \)
- B\( 0.2 \mathrm{~A} \)
- C\( 0.1 \mathrm{~A} \)
- D\( 0.3 \mathrm{~A} \)
Solution
(A)
\[ \begin{array}{l} R_{e q}=(1+2) \Omega=3 \Omega \\ I=\frac{V}{R_{e q}}=\frac{1.2}{3}=0.4 \mathrm{~A} \end{array} \]
\[ \begin{array}{l} R_{e q}=(1+2) \Omega=3 \Omega \\ I=\frac{V}{R_{e q}}=\frac{1.2}{3}=0.4 \mathrm{~A} \end{array} \]
Hence, the correct answer is option: 'A'.