Q231 / 240 · KCET 2026 · Physics

A source of frequency $\nu$ gives $6$ beats/second when sounded with a source of frequency $200$ Hz. The second Harmonic of frequency $2\nu$ of the source gives $8$ beats/second when sounded with a source of frequency $420$ Hz. The value of $\nu$ is

  • A
    $205$ Hz
  • Correct answer
    B
    $206$ Hz
  • C
    $195$ Hz
  • D
    $210$ Hz

Solution

Given that the source of frequency $\nu$ gives $6$ beats/second with a source of $200$ Hz:

$\nu = 200 \pm 6$

$\Rightarrow \nu = 206$ Hz or $194$ Hz

The second harmonic of the source has a frequency of $2\nu$. It gives $8$ beats/second with a source of $420$ Hz:

$2\nu = 420 \pm 8$

$\Rightarrow 2\nu = 428$ Hz or $412$ Hz

$\Rightarrow \nu = 214$ Hz or $206$ Hz

The common value satisfying both conditions is $\nu = 206$ Hz.

Answer: $206$ Hz

Hence, the correct answer is option: 'B'.

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