The energy of one mole of photons of radiation of wavelength $300 \mathrm{nm}$ is (Given : $\mathrm{h}=6.63\times {10}^{-34} \mathrm{J} \mathrm{s},{\mathrm{N}}_{\mathrm{A}}=6.02\times {10}^{23}{ \mathrm{mol}}^{-1}\mathrm{c}=3\times {10}^8 \mathrm{m}{ \mathrm{s}}^{-1}$)

• A

  $235 \mathrm{kJ}{ \mathrm{mol}}^{-1}$
• B

  $325 \mathrm{kJ}{ \mathrm{mol}}^{-1}$
• Correct answer
  C

  $399 \mathrm{kJ}{ \mathrm{mol}}^{-1}$
• D

  $435 \mathrm{kJ}{ \mathrm{mol}}^{-1}$

Hence, the correct answer is option: 'C'.