The correct order of $\mathrm{N}-$compounds in its decreasing order of oxidation states is

• A

  ${\mathrm{HNO}}_3,\mathrm{ }{\mathrm{NH}}_4\mathrm{Cl},\mathrm{ }\mathrm{NO},\mathrm{ }{\mathrm{N}}_2$
• B

  ${\mathrm{HNO}}_3,\mathrm{ }\mathrm{NO},\mathrm{ }{\mathrm{NH}}_4\mathrm{Cl},\mathrm{ }{\mathrm{N}}_2$
• Correct answer
  C

  ${\mathrm{HNO}}_3,\mathrm{ }\mathrm{NO},\mathrm{ }{\mathrm{N}}_2,{\mathrm{NH}}_4\mathrm{Cl}$
• D

  ${\mathrm{NH}}_4\mathrm{Cl},\mathrm{ }{\mathrm{N}}_2,\mathrm{ }\mathrm{NO},\mathrm{ }{\mathrm{HNO}}_3$

Solution

$\to {\mathrm{HNO}}_3\Rightarrow 1+\mathrm{x}+3(-2)=0$

$\mathrm{x}=5$

$\to \mathrm{NO}\Rightarrow \mathrm{x}+1(-2)=0$

$\mathrm{x}=2$

$\to {\mathrm{N}}_2\Rightarrow 2\mathrm{x}=0$

$\mathrm{x}=0$

$\to {\mathrm{NH}}_4\mathrm{Cl}=\mathrm{x}+4\left(1\right)+1(-1)=0$

$\mathrm{x}=-3$

Hence, the correct answer is option: 'C'.