Q79 / 180 · NEET 2026 (Cancelled) · Chemistry
Identify the incorrect statement from the following :
- ANitrogen can form $p\pi$-$p\pi$ multiple bonds with itself.
- B$\text{P}(\text{C}_2\text{H}_5)_3$ and $\text{As}(\text{C}_6\text{H}_5)_3$ form $d\pi$-$d\pi$ bond with transition metals.
- CPhosphorus, arsenic and antimony show catenation property.
- Correct answerDNitrogen can form $d\pi$-$p\pi$ bond with oxygen.
Solution
Nitrogen and oxygen both belong to the second period of the periodic table.
The valence shell electronic configuration of nitrogen is $2s^{2} 2p^{3}$ and that of oxygen is $2s^{2} 2p^{4}$.
Since the principal quantum number is $n=2$ for both elements, they do not have vacant d-orbitals in their valence shells.
Therefore, nitrogen cannot form $d\pi$-$p\pi$ bonds with oxygen. They can only form $p\pi$-$p\pi$ multiple bonds.
Statement (1) is correct as nitrogen forms $p\pi$-$p\pi$ multiple bonds with itself (e.g., in $N_{2}$).
Statement (2) is correct because phosphorus and arsenic have vacant d-orbitals and can act as $\pi$-acceptor ligands, forming $d\pi$-$d\pi$ back-bonds with the filled d-orbitals of transition metals.
Statement (3) is correct as phosphorus, arsenic, and antimony exhibit the property of catenation.
Thus, the incorrect statement is (4).
Answer: Nitrogen can form $d\pi$-$p\pi$ bond with oxygen.
The valence shell electronic configuration of nitrogen is $2s^{2} 2p^{3}$ and that of oxygen is $2s^{2} 2p^{4}$.
Since the principal quantum number is $n=2$ for both elements, they do not have vacant d-orbitals in their valence shells.
Therefore, nitrogen cannot form $d\pi$-$p\pi$ bonds with oxygen. They can only form $p\pi$-$p\pi$ multiple bonds.
Statement (1) is correct as nitrogen forms $p\pi$-$p\pi$ multiple bonds with itself (e.g., in $N_{2}$).
Statement (2) is correct because phosphorus and arsenic have vacant d-orbitals and can act as $\pi$-acceptor ligands, forming $d\pi$-$d\pi$ back-bonds with the filled d-orbitals of transition metals.
Statement (3) is correct as phosphorus, arsenic, and antimony exhibit the property of catenation.
Thus, the incorrect statement is (4).
Answer: Nitrogen can form $d\pi$-$p\pi$ bond with oxygen.
Hence, the correct answer is option: 'D'.