Q143 / 160 · AP EAMCET 2024 (21 May Shift 1) · Physics

The angle of polarisation for a medium with respect to air is $60^{\circ}$. The critical angle of this medium with respect to air is

  • A
    $\sin ^{-1} \sqrt{3}$
  • B
    $\tan ^{-1} \sqrt{3}$
  • C
    $\cos ^{-1} \sqrt{3}$
  • Correct answer
    D
    $\sin ^{-1} \frac{1}{\sqrt{3}}$

Solution

Angle of polarisation, $\mathrm{i}_{\mathrm{p}}=60^{\circ}$ $\therefore \quad \mu=\tan \mathrm{i}_{\mathrm{p}}=\tan 60^{\circ}=\sqrt{3}$ $\therefore \quad$ Critical angle, $C=\sin ^{-1}\left(\frac{1}{\mu}\right)=\sin ^{-1}\left(\frac{1}{\sqrt{3}}\right)$

Hence, the correct answer is option: 'D'.

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