A ray of light travels from an optically denser to rarer medium. The critical angle for the two media is ' $C$ '. The maximum possible deviation of the ray will be

• A

  $\frac{\pi}{2}-C$
• B

  $2 C$
• Correct answer
  C

  $\pi-2 C$
• D

  $\pi-C$

Solution

The deviation is given by $\begin{aligned} & \delta=\pi-2 \mathrm{i} \\ & \text { At } \mathrm{i}=\mathrm{C}, \delta=\delta_{\max } \\ & \therefore \quad \delta_{\max }=\pi-2 \mathrm{c} \end{aligned}$

Hence, the correct answer is option: 'C'.