Q74 / 155 · WBJEE 2024 · Mathematics

Let $f(x)=\left|\begin{array}{ccc}\cos x & x & 1 \\ 2 \sin x & x^3 & 2 x \\ \tan x & x & 1\end{array}\right|$, then $\lim _{x \rightarrow 0} \frac{f(x)}{x^2}=$

  • A
    2
  • Correct answer
    B
    -2
  • C
    1
  • D
    -1

Solution

Hint : $\begin{aligned} & f(x)=\left(x^3-2 x^2\right) \cos x+\tan x\left(2 x^2-x^3\right) \\ & \begin{aligned} \lim _{x \rightarrow 0} \frac{f(x)}{x^2} & =\lim _{x \rightarrow 0}(x-2) \cos x+\tan x(2-x) \\ & =-2 \end{aligned} \end{aligned}$

Hence, the correct answer is option: 'B'.

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