Q74 / 155 · WBJEE 2024 · Mathematics
Let $f(x)=\left|\begin{array}{ccc}\cos x & x & 1 \\ 2 \sin x & x^3 & 2 x \\ \tan x & x & 1\end{array}\right|$, then $\lim _{x \rightarrow 0} \frac{f(x)}{x^2}=$
- A2
- Correct answerB-2
- C1
- D-1
Solution
Hint :
$\begin{aligned}
& f(x)=\left(x^3-2 x^2\right) \cos x+\tan x\left(2 x^2-x^3\right) \\
& \begin{aligned}
\lim _{x \rightarrow 0} \frac{f(x)}{x^2} & =\lim _{x \rightarrow 0}(x-2) \cos x+\tan x(2-x) \\
& =-2
\end{aligned}
\end{aligned}$
Hence, the correct answer is option: 'B'.